Systems Using Substitution

Key Questions

  • Well, I would say that it is easier when you have few equations and variables. If you have 2 equations and 2 variables it is ok; when you get to 3 equations and 3 variables it becomes more complicated, it is still possible, but you have more work to do. The number of substitutions increases together with the possibility to make mistakes.
    More than 3 equations and 3 variables and it gets almost impossible and other methods would be better.

  • For an answer to have an infinite solution, the two equations when you solve will equal #0=0#.

    Here is a problem that has an infinite number of solutions.

    #3x+2y= 12#
    #-6x-4y=24#

    If you solve this your answer would be #0=0# this means the problem has an infinite number of solutions.

    For an answer to have no solution both answers would not equal each other.

    Here is a problem that has no solution.

    #4x-8y=5#
    #-3x+6y=11#

    Again, if you solve this your answer would be #0=59#, this is obviously not true, 0 does not equal 59 so this problem would have no solution.

  • Answer:

    Please see below.

    Explanation:

    I assume you are interested in linear equations. In general you need #n# equations if you have #n# variables.

    Let us have #3# equations and #3# variables #x,y# and #z#. Now pick up an equation with #x# and segregate it say #x# in terms of #y,z#. When we put this value of #x# in two other equations we get two equations in #y# and #z#.

    We can now find #y# in terms of #z# say using second equation and when we put in third equation we get value of #z#.

    Once #z# is known, it is easy to find #y# and then #x#.

Questions