How do you solve the following system: #2x-5y=-19, y + 4x = 16 #? Algebra Systems of Equations and Inequalities Systems Using Substitution 1 Answer Shwetank Mauria Apr 23, 2016 #x=3 17/22# and #y=4 10/11# Explanation: Putting value of #y# from #y+4x=16# i.e. #y=16-4x# in #2x-5y=-19#, we get #2x-5(16-4x)=-19# or #2x-80+20x=-19# or #22x=80-19=61# or #x=61/22=3 17/22# Now putting this in #y=16-4x# we get #y=16-(4xx61)/22# or #y=16-244/22=16-11 2/22=4 20/22=4 10/11# Answer link Related questions How do you solve systems of equations using the substitution method? How do you check your solutions to a systems of equations using the substitution method? When is the substitution method easier to use? How do you know if a solution is "no solution" or "infinite" when using the substitution method? How do you solve #y=-6x-3# and #y=3# using the substitution method? How do you solve #12y-3x=-1# and #x-4y=1# using the substitution method? Which method do you use to solve the system of equations #y=1/4x-14# and #y=19/8x+7#? What are the 2 numbers if the sum is 70 and they differ by 11? How do you solve #x+y=5# and #3x+y=15# using the substitution method? What is the point of intersection of the lines #x+2y=4# and #-x-3y=-7#? See all questions in Systems Using Substitution Impact of this question 1303 views around the world You can reuse this answer Creative Commons License