How do you solve the following system: $2x-5y=-19, y + 4x = 16$ ?

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Answer 1 · 2016-04-23T09:21:14

$x=3 17/22$ and $y=4 10/11$

Putting value of $y$ from $y+4x=16$ i.e. $y=16-4x$ in $2x-5y=-19$ , we get

$2x-5(16-4x)=-19$ or

$2x-80+20x=-19$ or

$22x=80-19=61$ or $x=61/22=3 17/22$

Now putting this in $y=16-4x$ we get $y=16-(4xx61)/22$ or

$y=16-244/22=16-11 2/22=4 20/22=4 10/11$

How do you solve the following system: 2x-5y=-19, y + 4x = 16 2x-5y=-19, y + 4x = 16 ?