Question #ad7f5

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Answer 1 · 2016-12-09T21:16:40

The solution to this problem is the null set or #{O/}#

Chandler, because the second equation is already solved for #y# we can substitute #-3x + 4# for #y# in the first equation and solve:

#3x + (-3x + 4) = 10#

#3x - 3x + 4 = 10#

#0 + 4 = 10#

Oops,

#4 != 10#

Because 4 does not equal 10 the solution to this problem is the null set or #{O/}#