How do you solve the following system?: $6x - 4y = 3 , 5x - 2y = 1$

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Answer 1 · 2015-12-02T11:14:59

$x=(-1)/4$
$y=(-9)/8$

$6x-4y=3$ --------------(1)
$5x-2y=1$ ------------------(2)
Let us have the equations as -

We are going to eliminate $y$

Before that understand $-4y +4y =0$

Multiply equation (2) with $-2$

$6x-4y=3$ ------------------(1)
$-10x+4y=-2$ ------------------(2)

Add (1) and (2), we get -

$-4x=1$
$x=(-1)/4$

Substitute $x=(-1)/4$ in equation (1)

$6((-1)/4)-4y=3$
$(-6)/4-4y=3$
$(-3)/2-4y=3$
$-4y = 3+3/2=(6+3)/2=9/2$
$y=9/2 xx1/(-4)=(-9)/8$

How do you solve the following system?: 6x - 4y = 3 , 5x - 2y = 1 6x - 4y = 3 , 5x - 2y = 1