How do you solve x+y=6 and x-y=2?

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Answer 1 · 2016-03-27T08:49:25

$(x,y)=(4,2)$

$color(blue)(x+y=6$

$color(blue)(x-y=2$

We can get rid of $y$ in the first equation by $-y$ in the second equation.

$:.$ Add the equations

$rarr(x+y=6)+(x-y=2)$

$rarr2x=8$

$rArrcolor(green)(x=8/2=4$

Substitute the value of $x$ to the first equation

$rarr4+y=6$

$rarry=6-4$

$rArrcolor(green)(y=2$