How do you solve the following linear system: $y = 4x - 13 , y = 1/2x - 3/2$ ?

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Answer 1 · 2015-11-14T14:50:02

$(23/7, 1/7) in mathbb{Q times Q}$

$y = 4x - 13 = 1/2 x - 3/2$ // times two

$2y = 8x- 26 = x - 3$

$8x -x = -3 + 26$

$x = 23/7$

$y = 4 cdot 23/7 - 13$

How do you solve the following linear system: y = 4x - 13 , y = 1/2x - 3/2 y = 4x - 13 , y = 1/2x - 3/2 ?