How do you solve $x-5y=15$ and $4x-3y=26$ using substitution?

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Answer 1 · 2015-02-05T20:11:57

you can isolate $x$ from the first equation giving:
$x=5y+15$ and substitute in the second:
$4(5y+15)-3y=26$
$20y+60-3y=26$
$17y=-34$
$y=-2$

Substituting back in: $x=5y+15$ it gives you:
$x=-10+15=5$

How do you solve x-5y=15x-5y=15 and 4x-3y=264x-3y=26 using substitution?