How do you solve the following system: $5 x + y = - 7, 5 x + 3 y = - 1$ $5x+y=-7 , 5x+3y=-1$ ?

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How do you solve the following system: $5 x + y = - 7, 5 x + 3 y = - 1$ $5x+y=-7 , 5x+3y=-1$ ?

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Answer 1 · 2016-01-07T11:38:11

$x = - 2; y = 3$ $x=-2 ; y=3$

Explanation:

$5 x + y = - 7$ $5x + y = -7$ (1)
$5 x + 3 y = - 1$ $5x +3y = -1$ (2)

Subtracting Equation (1) from Eqation(2) we get,
2y = 6 or $y = 3$ $y = 3$ Putting y =3 in Equation (1) We get $5 \cdot x = - 7 - 3$ $5*x=-7-3$ or
$x = - 2$ $x=-2$ $:. x= -2 ; y=3$ [Answer]

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How do you solve the following system: $5 x + y = - 7, 5 x + 3 y = - 1$ $5x+y=-7 , 5x+3y=-1$ ?

1 Answer

Explanation:

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Science

Math

Humanities

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How do you solve the following system: 5x+y=-7 , 5x+3y=-1 5x+y=−7,5x+3y=−1 5x+y=-7 , 5x+3y=-1 ?

1 Answer

Explanation:

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Impact of this question

How do you solve the following system: $5 x + y = - 7, 5 x + 3 y = - 1$ $5x+y=-7 , 5x+3y=-1$ ?