How do you solve the following system?: $- x + 4 y = 8, x - 5 y = 4$ $-x+4y=8 , x-5y=4$

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Answer 1 · 2015-12-22T17:15:57

The solution for the system of equations is

$x = - 56, y = - 12$ $color(blue)(x=-56, y=-12$

$- x + 4 y = 8$ $color(blue)(-x) +4y=8$ .......equation $(1)$ $(1)$

$x - 5 y = 4$ $color(blue)(x) -5y=4$ ............equation $(2)$ $(2)$

Solving by elimination:

Adding the two equations would result in an elimination of $x$ $x$ :

$cancelcolor(blue)(-x) +4y=8$

$cancelcolor(blue)(x) -5y=4$

$-y=12$

$color(blue)(y=-12$

Finding $x$ by substituting $y$ in equation $1$ :

$-x +4y=8$

$4y-8=x$

$-48-8=x$

$-56=x$

$color(blue)(x=-56$

How do you solve the following system?: -x+4y=8 , x-5y=4 −x+4y=8,x−5y=4 -x+4y=8 , x-5y=4