How do you solve the following system?: $x + 3 y = 6, - x + y = - 3$ $x+3y=6, -x+y=-3$

Question

How do you solve the following system?: $x + 3 y = 6, - x + y = - 3$ $x+3y=6, -x+y=-3$

1 Answer

Impact of this question

1327 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-02-01T18:13:00

I found:
$x = \frac{15}{4}$ $x=15/4$
$y = \frac{3}{4}$ $y=3/4$

Explanation:

I would try to add in columns the two equations:
${(x+3y=6),(-x+y=-3):}$
$color(red)(0+4y=3$
so that $y=3/4$
substitute this value into the first equation:
$x+(3*color(blue)(3/4))=6$
$4x+9=24$
$x=15/4$

Science

Math

Humanities

... and beyond

How do you solve the following system?: $x + 3 y = 6, - x + y = - 3$ $x+3y=6, -x+y=-3$

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you solve the following system?: x+3y=6, -x+y=-3 x+3y=6,−x+y=−3 x+3y=6, -x+y=-3

1 Answer

Explanation:

Related questions

Impact of this question

How do you solve the following system?: $x + 3 y = 6, - x + y = - 3$ $x+3y=6, -x+y=-3$