How do you solve the following system: x + 8y = 15 , 4x + y = -1 ?

1 Answer
Jan 30, 2016

The solution is x=-0.74, y=1.97.

See the explanation below.

Explanation:

Call the two equations (1) and (2) as follows to make it easier to explain:

x+8y=15 (1)
4x+y=-1 (2)

Multiply (1) by 4 and call it (1'):

4x + 32y = 60 (1')

Subtract (2) from (1') (we are doing this to eliminate x so we have only one variable in play)

4x + 32y = 60 (1') minus
4x+y=-1 (2)

Result:

31y=61

Divide both sides by 31:

#y=61/31 (or 1.97)

Now plug this value back into one of the original equations to find the value of x. It's probably simpler to use (1):

x+8(61/31)=15
x=15-8(61/31) = -0.74

(too messy for me to do it in fractions, but you're in the UK not the US so you can probably handle decimals. ;-))

(you can test these solutions by plugging both into either of the original equations and ensuring that it's true (i.e. that both sides are equal, within rounding error))