How do solve the following linear system?: # x/2 - y/4 = -1 , 2/3x + 4y = -1 #?

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Answer 1 · 2016-02-07T17:23:10

#x=-51/26# and #y=1/13#

(a) #x/2-y/4=-1#

(b) #2/3x+4y=-1#

First eliminate the fractions, multiplying (a) by 4 and (b) by 3:

(a) #2x-y=-4#

(b) #2x+12y=-3#

Do (b)-(a):

#13y=1 =>y=1/13#

For x, replace y in (a)

#2x-1/13=-4#
#2x=-4+1/13#
#2x=-51/13#
#x=-51/26#