How do you solve the system #2x + y = 1# and #4x + 2y = −1# by substitution?
1 Answer
May 26, 2015
Given
We would normally rearrange [1] to get an equation for
and then substitute this value into equation [2] to solve for
but
Notice something unusual in this case
The left-side of [2] is exactly 2 times the left-side of [1]
but the right-side of [2] is not 2 times the right-side of [1].
The given equations are a pair of parallel lines with no solution (since they do not intersect).
