How do you solve the following linear system: $x - 5 y = 3, 2 x - 10 y = - 3$ $x - 5y = 3, 2x - 10y = -3$ ?

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Answer 1 · 2018-03-29T05:50:36

the lines are parallel

They do not intersect

$x - 5 y = + 3$ $x-5y=+3$

$2 x - 10 y = - 3$ $2x-10y=-3$

Here,
Differentiating line 1 wrt x
Slope of line 1 is

$1 - 5 \frac{d y}{d x} = 0$ $1-5dy/dx=0$

$\frac{d y}{d x} = \frac{1}{5}$ $dy/dx=1/5$
Differentiating line 2 wrt x
Slope of line 2 is

$2 - 10 \frac{d y}{d x} = 0$ $2-10dy/dx=0$

$\frac{d y}{d x} = \frac{2}{10} = \frac{1}{5}$ $dy/dx=2/10=1/5$

the lines are parallel

They do not intersect

How do you solve the following linear system: x−5y=3,2x−10y=−3x - 5y = 3, 2x - 10y = -3 ?