How do you find the point of intersection for $3 x - y = - 4$ $3x-y= -4$ and $3 x - y = 0$ $3x-y=0$ ?

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Answer 1 · 2015-07-12T23:45:08

These equations are of parallel lines, with no intersection.

If you try to satisfy both equations with the same values of $x$ $x$ and $y$ $y$ then you find:

$- 4 = 3 x - y = 0$ $-4 = 3x - y = 0$

Both equations have the same coefficients of $x$ $x$ and $y$ $y$ but different constant terms. They represent parallel lines:

graph{(3x-y+4)(3x-y) = 0 [-10, 10, -5, 5]}

How do you find the point of intersection for 3x-y= -43x−y=−43x-y= -4 and 3x-y=03x−y=03x-y=0?