How do you find the coordinates of the point of intersection for the pair of lines whose equations y=2x-1 and x+2y=8?

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How do you find the coordinates of the point of intersection for the pair of lines whose equations y=2x-1 and x+2y=8?

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Answer 1 · 2015-09-16T17:14:09

$x = 2 and y = 3$ $x = 2 and y = 3$

Explanation:

$y = 2 x - 1$ $y = 2x - 1$ . . . .(1)
$x + 2 y = 8$ $x + 2y = 8$ . . . . (2)
(1) * 2 = 2y = 4x - 2 . . . .(3)
(2) - (3) = x = 8 - 4x + 2
i.e., $4 x + x = 5 x = 8 + 2 = 10$ $4x + x = 5x = 8 + 2 = 10$
or $x = \frac{10}{5} = 2$ $x = 10 / 5 = 2$
$y = 2 \cdot 2 - 1 = 3$ $y = 2 * 2 - 1 = 3$

Answer 2 · 2015-09-16T17:15:44

I found:
$x = 2$ $x=2$
$y = 3$ $y=3$

Explanation:

You can use the value of $y$ $y$ from the first equation and substitute into the second to get:
$x + 2 (2 x - 1) = 8$ $x+2(color(red)(2x-1))=8$ and solve for $x$ $x$ :
$x + 4 x - 2 = 8$ $x+4x-2=8$
$5 x = 10$ $5x=10$
$x = \frac{10}{5} = 2$ $x=10/5=2$
use this value back into the first equation to find $y$ $y$ :
$y = 2 \cdot 2 - 1 = 4 - 1 = 3$ $y=2*2-1=4-1=3$

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How do you find the coordinates of the point of intersection for the pair of lines whose equations y=2x-1 and x+2y=8?

2 Answers

Explanation:

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