How do you solve the system of equations $3x - 2y = 4$ and $2x + 3y = - 6$ ?

Question

7975 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-30T16:43:10

$x=0$ and $y=-2$

Multiplying the first equation by $3$ and the second one by $2$
and adding both we get

$13x=0$ so $x=0$
With $x=0$ we get

$y=-2$

How do you solve the system of equations 3x - 2y = 43x - 2y = 4 and 2x + 3y = - 62x + 3y = - 6?