How do you solve the system #−3x + y = 2# and #4x + 2y = 4#?

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How do you solve the system #−3x + y = 2# and #4x + 2y = 4#?

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Answer 1 · 2015-05-29T09:04:41

#-3x + y =3 => y = 3 +3x # ;
#4x + 2y = 4 => 4x + 2*(3+3x)= 4 => 4x+6+6x=4 #
# => 10x +6 =4 => 10x =-2 => x=-2/10=-1/5 #
#y=3+3x => y=3+3*(-1/5) => y= 3-3/5 => y= 15/5 - 3/5 #
# y= 12/5 #

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How do you solve the system #−3x + y = 2# and #4x + 2y = 4#?

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