How do you solve by substitution #x=3-3y# and #4y=x+11#?
1 Answer
Mar 8, 2018
Explanation:
#x=3-3yto(1)#
#4y=x+11to(2)#
#"since equation "(1)" gives x in terms of y we can "color(blue)"substitute ""it directly into equation "(2)#
#4y=3-3y+11#
#"add 3y to both sides"#
#4y+3y=3cancel(-3y)cancel(-3y)+11#
#rArr7y=14#
#"divide both sides by 7"#
#(cancel(7) y)/cancel(7)=14/7#
#rArry=2#
#"substitute "y=2" into equation "(1)#
#x=3-(3xx2)=-3#
#"solution is "x=-3" and "y=2#
