How do you solve the following system?: #-x -8y =-3, 6x -4y = -4#

Question

How do you solve the following system?: #-x -8y =-3, 6x -4y = -4#

1 Answer

Impact of this question

1004 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-06T13:57:57

#x=-175/11,y=26/11#

Explanation:

Writing your System in the form
#-x-8y=-3#
#3x-2y=-2#
Multiplying the first equation by #3# and adding to the second we get
#-26y=-11#
so
#y=26/11#
we get
#-x=-3+8*26/11#
#x=-175/11#

Science

Math

Humanities

... and beyond

How do you solve the following system?: #-x -8y =-3, 6x -4y = -4#

1 Answer

Explanation:

Related questions

Impact of this question