How do you solve the following system?: # 2x+3y=11, -x+y=-3 #

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Answer 1 · 2015-12-05T03:39:15

The solution for the system of equations is
#color(blue)(x=4,y=1#

#color(blue)(2x)+3y=11#.....................equation #1#

#-x+y = -3# ,multiplying this equation by #2#
#color(blue)(-2x)+2y = -6#..............equation #2#

Solving by elimination .

Adding equations #1 #and #2# would result in elimination of the term #color(blue)(2x#.

#cancelcolor(blue)(2x)+3y=11#
#cancelcolor(blue)(-2x)+2y = -6#

#5y=5#

#y=5/5#

#color(blue)(y=1#

Now we substitute the value of #y# in equation #2# to find #x#:
#-x+y = -3#

#y +3= x#

#1 +3= x#

#color(blue)(x=4#