How do you solve the system $x - 4 y = - 8$ $x-4y=-8$ and $- 3 x + 12 y = 24$ $-3x+12y=24$ ?

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How do you solve the system $x - 4 y = - 8$ $x-4y=-8$ and $- 3 x + 12 y = 24$ $-3x+12y=24$ ?

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Answer 1 · 2015-05-15T18:11:05

There an infinite number of solutions to this pair of equations since they are really the same equation. The second equation is just $(- 3)$ $(-3)$ times the first one.

If you tried to plot them as lines (where the solution would normally be the point where the lines intersect) you would only get one line.

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How do you solve the system $x - 4 y = - 8$ $x-4y=-8$ and $- 3 x + 12 y = 24$ $-3x+12y=24$ ?

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How do you solve the system x−4y=−8x-4y=-8 and −3x+12y=24-3x+12y=24?

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How do you solve the system $x - 4 y = - 8$ $x-4y=-8$ and $- 3 x + 12 y = 24$ $-3x+12y=24$ ?