Given:
#" "x=y-2#..................Equation(1)
#" "3x-y=6#...............Equation(2)
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#color(green)("Determine the value of "y)#
#color(purple)("Method shown in great detail")#
Substitute for #x# in equation(2) using equation(1)
#color(brown)(3x-y=6)color(blue)(" "->" "3(y-2)-y=6#
#3y-6-y=6#
#2y-6=6#
Add 6 to both sides
#2y-6+6=6+6#
#2y+0=12#
Divide both sides by 2
#2/2xx y=12/2#
#color(green)(y=6)#
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#color(green)("Determine the value of "x)#
Given that #y=6# equation(1) becomes:
#x=6-2" "........................Equation(1_a)#
#color(green)(x=4)#