Question #bef4d

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Question #bef4d

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Answer 1 · 2016-09-17T21:18:12

$x = 4; y = 6$ $x=4"; "y=6$

Explanation:

Given:
$x = y - 2$ $" "x=y-2$ ..................Equation(1)
$3 x - y = 6$ $" "3x-y=6$ ...............Equation(2)
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
$Determine the value of y$ $color(green)("Determine the value of "y)$

$Method shown in great detail$ $color(purple)("Method shown in great detail")$

Substitute for $x$ $x$ in equation(2) using equation(1)

$3 x - y = 6 \to 3 (y - 2) - y = 6$ $color(brown)(3x-y=6)color(blue)(" "->" "3(y-2)-y=6$

$3 y - 6 - y = 6$ $3y-6-y=6$

$2 y - 6 = 6$ $2y-6=6$

Add 6 to both sides

$2 y - 6 + 6 = 6 + 6$ $2y-6+6=6+6$

$2 y + 0 = 12$ $2y+0=12$

Divide both sides by 2

$\frac{2}{2} \times y = \frac{12}{2}$ $2/2xx y=12/2$

$y = 6$ $color(green)(y=6)$
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
$Determine the value of x$ $color(green)("Determine the value of "x)$

Given that $y = 6$ $y=6$ equation(1) becomes:

$x=6-2" "........................Equation(1_a)$

$color(green)(x=4)$

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Question #bef4d

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