Question #bef4d

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Question #bef4d

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Answer 1 · 2016-09-17T21:18:12

$x=4"; "y=6$

Explanation:

Given:
$" "x=y-2$ ..................Equation(1)
$" "3x-y=6$ ...............Equation(2)
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
$color(green)("Determine the value of "y)$

$color(purple)("Method shown in great detail")$

Substitute for $x$ in equation(2) using equation(1)

$color(brown)(3x-y=6)color(blue)(" "->" "3(y-2)-y=6$

$3y-6-y=6$

$2y-6=6$

Add 6 to both sides

$2y-6+6=6+6$

$2y+0=12$

Divide both sides by 2

$2/2xx y=12/2$

$color(green)(y=6)$
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
$color(green)("Determine the value of "x)$

Given that $y=6$ equation(1) becomes:

$x=6-2" "........................Equation(1_a)$

$color(green)(x=4)$

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Question #bef4d

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