How do you solve the following system?: 3x + y = -1 , 2x – y = -4

1 Answer
May 28, 2018

See a solution process below:

Explanation:

Step 1) Solve the first equation for y:

3x + y = -1

3x - color(red)(3x) + y = -1 - color(red)(3x)

0 + y = -1 - 3x

y = -1 - 3x

Step 2) Substitute (-1 - 3x) for y in the second equation and solve for x:

2x - y = -4 becomes:

2x - (-1 - 3x) = -4

2x + 1 + 3x = -4

2x + 3x + 1 = -4

(2 + 3)x + 1 = -4

5x + 1 = -4

5x + 1 - color(red)(1) = -4 - color(red)(1)

5x + 0 = -5

5x = -5

(5x)/color(red)(5) = -5/color(red)(5)

(color(red)(cancel(color(black)(5)))x)/cancel(color(red)(5)) = -1

x = -1

Step 3) Substitute -1 for x in the solution to the first equation at the end of Step 1 and calculate y:

y = -1 - 3x becomes:

y = -1 - (3 xx -1)

y = -1 - (-3)

y = -1 + 3

y = 2

The Solution Is:

x = -1 and y = 2

Or

(-1, 2)