How do you solve #-2x + y = -1# and #x + y = 5# using substitution?

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Answer 1 · 2017-05-09T05:40:15

#x = 2, y = 3#

#-2x + y = -1#...................................(i)
#x + y = 5#................................................(ii)

From (i),
#y = 2x - 1#............................(iii)

Substituting y = 2x -1 in eq(ii),

#x + (2x - 1) = 5#

#rArr# #x +2x - 1 = 5#

#rArr# #3x = 6#

#rArr# #x = 2#

Substituting x = 2 in eq (ii),
#2 + y = 5#

#rArr# #y = 3#