How do you solve #7x+y= 11# and #3x+2y= -11# using substitution?

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Answer 1 · 2018-03-30T08:35:45

#x = 3 and y =-10#

Rearrange the first equation to get:

#y = 11 - 7x#

Substitute this into the second equation:

#3x + 2(11 - 7x) = -11#

Expand the bracket:

#3x + 22 - 14x = -11#

#22 - 11x = -11#

#33 = 11x#

#x =3#

Now substitute #x = 3# into any of the three equations to find #y#:
#y = 11 - 7x# #=># #y = 11 - 21#

#y =-10#