How do you solve the following system?: $-2x -8y =3, 3x -2y = -3$

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Answer 1 · 2016-06-01T00:49:39

To substitute, we need to solve for one of the variables and then substitute this into the other equation.

$-2x = 3 + 8y$

$x = -3/2 - 4y$

$:. 3(-3/2 - 4y) - 2y = -3$

$-9/2 - 12y - 2y = -3$

$-14y = -3 + 9/2$

$-14y = 3/2$

$y = (3/2)/-14$

$y = -3/28$

Solving for x:

$3x - 2(-3/28) = -3$

$3x + 6/28 = -3$

$3x = -3 - 3/14$

$3x = -42/14 - 3/14$

$3x = -45/14$

$x = -45/42$

$x = -15/14$

Therefore, the solution set is ${-15/14, -3/28}$ . Don't forget solutions always have to be presented in the form ${x, y}$ .

Hopefully this helps!

How do you solve the following system?: -2x -8y =3, 3x -2y = -3-2x -8y =3, 3x -2y = -3