How do you solve 5x+y=1 and 3x+2y=2 using substitution?

2 Answers
Mar 5, 2018

color(green)(x = 0, y = 1

Explanation:

5x + y = 1 Eqn (1)

y = 1 - 5x

3x + 2y = 2 Eqn (2)

Substituting value of y in second equation in terms of x,

3x + (2* (1-5x) = 2

3x + 2 - 10x = 2

-7x = 2 - 2 = 0 or x = 0

Substituting value of x in Equation (1),

(5*0) + y = 1 or y = 1

Solution color(green)(x = 0, y = 1)

Mar 5, 2018

x=0
y=1

Explanation:

Given -

5x+y=1 ---------------(1)
3x+2y=2 ---------------(2)

5x+y=1 ---------------(1)xx2
10x+2y=2 ------(3)
3x+2y=2 -------(2) (3) - (2)
7x=0
x=0/7=0

Substitute x=0 in equation (1)

5(0)+y=1
y=1