How do you solve $5 x + y = 1$ $5x+y=1$ and $3 x + 2 y = 2$ $3x+2y=2$ using substitution?

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How do you solve $5 x + y = 1$ $5x+y=1$ and $3 x + 2 y = 2$ $3x+2y=2$ using substitution?

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Answer 1 · 2018-03-05T06:59:25

$x = 0, y = 1$ $color(green)(x = 0, y = 1$

Explanation:

$5 x + y = 1$ $5x + y = 1$ Eqn (1)

$y = 1 - 5 x$ $y = 1 - 5x$

$3 x + 2 y = 2$ $3x + 2y = 2$ Eqn (2)

Substituting value of y in second equation in terms of x,

$3 x + (2 \cdot (1 - 5 x) = 2$ $3x + (2* (1-5x) = 2$

$3 x + 2 - 10 x = 2$ $3x + 2 - 10x = 2$

$- 7 x = 2 - 2 = 0$ $-7x = 2 - 2 = 0$ or $x = 0$ $x = 0$

Substituting value of x in Equation (1),

$(5 \cdot 0) + y = 1$ $(5*0) + y = 1$ or $y = 1$ $y = 1$

Solution $x = 0, y = 1$ $color(green)(x = 0, y = 1)$

Answer 2 · 2018-03-05T07:00:02

$x = 0$ $x=0$
$y = 1$ $y=1$

Explanation:

Given -

$5 x + y = 1$ $5x+y=1$ ---------------(1)
$3 x + 2 y = 2$ $3x+2y=2$ ---------------(2)

$5 x + y = 1$ $5x+y=1$ ---------------(1) $\times 2$ $xx2$
$10 x + 2 y = 2$ $10x+2y=2$ ------(3)
$3 x + 2 y = 2$ $3x+2y=2$ -------(2) $(3) - (2)$ $(3) - (2)$
$7 x = 0$ $7x=0$
$x = \frac{0}{7} = 0$ $x=0/7=0$

Substitute $x = 0$ $x=0$ in equation (1)

$5 (0) + y = 1$ $5(0)+y=1$
$y = 1$ $y=1$

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How do you solve $5 x + y = 1$ $5x+y=1$ and $3 x + 2 y = 2$ $3x+2y=2$ using substitution?

2 Answers

Explanation:

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How do you solve $5 x + y = 1$ $5x+y=1$ and $3 x + 2 y = 2$ $3x+2y=2$ using substitution?