What is $x$ $x$ and $y$ $y$ in this system of equations: $y + x = 6$ $y+x =6$ and $3 y - x = 3$ $3y -x = 3$ ?

Question

1916 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-23T16:04:53

$x = \frac{15}{4}$ $x=15/4$
$y = \frac{9}{4}$ $y=9/4$

Solve using the method of addition/ elimination

$y + x = 6$ $y+x=6$
$3 y - x = 3$ $3y-x=3$

Add the first equation to the second

$4 y = 9$ $4y=9$

$y = \frac{9}{4}$ $y=9/4$

Substitute the value of $y$ $y$ into any of the orignila equations to solve for $x$ $x$

$y + x = 6$ $y+x=6$

$\frac{9}{4} + x = 6$ $9/4+x=6$

$x = \frac{15}{4}$ $x=15/4$

Writing that as a point would be $(x, y)$ $(x,y)$

$\Rightarrow (\frac{15}{4}, \frac{9}{4})$ $rArr(15/4,9/4)$

What is xxx and yyy in this system of equations: y+x =6y+x=6y+x =6 and 3y -x = 33y−x=33y -x = 3?