How do you solve the following system?: $- 2 x + 5 y = - 6, 5 x + 6 y = - 1$ $-2x +5y =-6 , 5x +6y = -1$

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How do you solve the following system?: $- 2 x + 5 y = - 6, 5 x + 6 y = - 1$ $-2x +5y =-6 , 5x +6y = -1$

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Answer 1 · 2016-07-11T10:31:06

$x = \frac{31}{37}, y = - \frac{32}{37}$ $x = 31/37, y = -32/37$

Explanation:

We can solve for $y$ $y$ first by multiplying the first equation by $5$ $5$ and the second equation by $2$ $2$ :

$5 (- 2 x + 5 y) = (- 6) 5$ $5(-2x + 5y) = (-6)5$ and $2 (5 x + 6 y) = (- 1) 2$ $2(5x + 6y) = (-1)2$

Then we add the two equations, resulting in:

$25 y + 12 y = - 32$ $25y + 12y = -32$ , and therefore, $37 y = - 32$ $37y = -32$

We divide both sides by $37$ $37$ , so $y = - \frac{32}{37}$ $y = -32/37$

To solve for $x$ $x$ , we multiply the first equation by $- 6$ $-6$ and the second equation by $5$ $5$ :

$- 6 (- 2 x + 5 y) = - 6 (- 6)$ $-6(-2x + 5y) = -6(-6)$ and $5 (5 x + 6 y) = 5 (- 1)$ $5(5x + 6y) = 5(-1)$

Then we add the two equations, resulting in:

$12 x + 25 x = 31$ $12x + 25x = 31$ , and therefore, $37 x = 31$ $37x = 31$

We divide both sides by $37$ $37$ , so $x = \frac{31}{37}$ $x = 31/37$

You can verify these answers by substituting $\frac{31}{37}$ $31/37$ for $x$ $x$ and $- \frac{32}{37}$ $-32/37$ for $y$ $y$ :

$- 2 (\frac{31}{37}) + 5 (- \frac{32}{37}) = - \frac{62}{37} - \frac{160}{37} = - \frac{222}{37} = - 6$ $-2(31/37) + 5(-32/37) = -62/37 - 160/37 = -222/37 = -6$

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How do you solve the following system?: $- 2 x + 5 y = - 6, 5 x + 6 y = - 1$ $-2x +5y =-6 , 5x +6y = -1$

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you solve the following system?: −2x+5y=−6,5x+6y=−1 -2x +5y =-6 , 5x +6y = -1

1 Answer

Explanation:

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How do you solve the following system?: $- 2 x + 5 y = - 6, 5 x + 6 y = - 1$ $-2x +5y =-6 , 5x +6y = -1$