How do solve the following linear system?: # 3x - 2y = -6 , x/3 + 3y = 9 #?

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Answer 1 · 2016-07-05T10:42:30

x=0, y=3

First you can multiply all the terms of the second equation by 3 and then find x:

#x/3+3y=9 harr x+9y=27#

#x=-9y+27#

then you can substitute in x the expression #-9y+27# in the first equation:

#3(-9y+27)-2y=-6#

#-27y+81-2y+6=0#

#-29y=-87#

#y=87/29=3#

so

#x=-9(3)+27=0#