How do solve the following linear system?: $3x - 2y = -6 , x/3 + 3y = 9$ ?

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Answer 1 · 2016-07-05T10:42:30

x=0, y=3

First you can multiply all the terms of the second equation by 3 and then find x:

$x/3+3y=9 harr x+9y=27$

$x=-9y+27$

then you can substitute in x the expression $-9y+27$ in the first equation:

$3(-9y+27)-2y=-6$

$-27y+81-2y+6=0$

$-29y=-87$

$y=87/29=3$

so

$x=-9(3)+27=0$

How do solve the following linear system?: 3x - 2y = -6 , x/3 + 3y = 9 3x - 2y = -6 , x/3 + 3y = 9 ?