How do you solve the system of equations: y = 3x - 4 and 2x - y = 1?

Question

How do you solve the system of equations: y = 3x - 4 and 2x - y = 1?

2 Answers

Impact of this question

3359 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-09-17T16:21:00

I found:
$x=3$
$y=5$

Explanation:

You can substitute the value of $y$ from the first equation into the second and solve for $x$ as:
$2x-color(red)([3x-4])=1$
$2x-3x+4=1$
$-x=-3$
$x=3$
substitute back this value into the first equation to find $y$ :
$y=3*(3)-4=5$

Answer 2 · 2015-09-17T16:33:16

Refer to explanation

Explanation:

We have two equations

$y=3x-4$ and $y=2x-1$ Multiply the first with 2 and the second with three and substract them

$2y-3y=2*(3x-4)-3(2x-1)=>-y=-5=>y=5$ and $x=3$

Science

Math

Humanities

... and beyond

How do you solve the system of equations: y = 3x - 4 and 2x - y = 1?

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question