How do solve the following linear system?: x-3y=-1 , 3y = 15 -6x ?
1 Answer
Jun 27, 2018
Explanation:
x-3y=-1to(1)
3y=15-6xto(2)
"from "(1)" we obtain "x=3y-1to(3)
"substitute "x=3y-1" in equation "(2)
3y=15-6(3y-1)
3y=15-18y+6
"add "18y" to both sides"
21y=21rArry=21/21=1
"substitute "y=1" into equation "(3)
x=3-1=2
"point of intersection "=(2,1)
graph{(y-1/3x-1/3)(y+2x-5)=0 [-10, 10, -5, 5]}