How do you solve the following system?: $4 x - y = - 1, 4 x - 3 y = 15$ $4x-y=-1 , 4x-3y=15$

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Answer 1 · 2015-12-23T16:38:58

The solution for the system of equations is
$x = - \frac{9}{4}, y = - 8$ $color(blue)(x=-9/4,y=-8$

$4 x - y = - 1$ $color(blue)(4x)-y=-1$ .......equation $(1)$ $(1)$

$4 x - 3 y = 15$ $color(blue)(4x)-3y=15$ .........equation $(2)$ $(2)$

Solving by elimination

Subtracting equation $2$ $2$ from $1$ $1$

$cancelcolor(blue)(4x)-y=-1$
$cancel(-color(blue)(4x))+3y=-15$

$2y=-16$

$y=(-16)/2$

$color(blue)(y=-8$

Finding $x$ by substituting $y$ in equation $1$ :
$4x-y=-1$

$4x=-1+y$

$4x=-1-8$

$4x=-9$

$color(blue)(x=-9/4$

How do you solve the following system?: 4x-y=-1 , 4x-3y=15 4x−y=−1,4x−3y=154x-y=-1 , 4x-3y=15