How do you solve the following system: 29=5y3x,4x5y=1?

1 Answer
Jan 17, 2018

Solve the former one first
29=5y3x
Solve for y
Transfer 3x
3x29=5y
You can also transfer the 5 in 5y but that would be stupid considering that the next equation wants 5y
The latter equation
4x5y=1
Put the value of 5y
4x(3x29)=1
Which gives us
4x3x+29=1
Solve
x+29=1
Transfer the 1
x+29+1=0
x+30=0
Which gives
x=30
5y=3x29
Put value of x
5y=3×(30)29
Solve
5y=9029
Solve
5y=119
Transfer 5
y=1195
Or...
y=23.8