How do you solve the following system: $-29=5y-3x, 4x-5y= -1$ ?

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How do you solve the following system: $-29=5y-3x, 4x-5y= -1$ ?

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Answer 1 · 2018-01-17T09:33:23

Solve the former one first
$-29=5y-3x$
Solve for $y$
Transfer $3x$
$3x-29=5y$
You can also transfer the $5$ in $5y$ but that would be stupid considering that the next equation wants $5y$
The latter equation
$4x-5y=-1$
Put the value of $5y$
$4x-(3x-29)=-1$
Which gives us
$4x-3x+29=-1$
Solve
$x+29=-1$
Transfer the $-1$
$x+29+1=0$
$x+30=0$
Which gives
$x=-30$
$5y=3x-29$
Put value of $x$
$5y=3xx(-30)-29$
Solve
$5y=-90-29$
Solve
$5y=-119$
Transfer $5$
$y=-119/5$
Or...
$y=-23.8$

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How do you solve the following system: $-29=5y-3x, 4x-5y= -1$ ?

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How do you solve the following system: -29=5y-3x, 4x-5y= -1 -29=5y-3x, 4x-5y= -1 ?

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How do you solve the following system: $-29=5y-3x, 4x-5y= -1$ ?