How do you solve the following system: $- 29 = 5 y - 3 x, 4 x - 5 y = - 1$ $-29=5y-3x, 4x-5y= -1$ ?

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How do you solve the following system: $- 29 = 5 y - 3 x, 4 x - 5 y = - 1$ $-29=5y-3x, 4x-5y= -1$ ?

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Answer 1 · 2018-01-17T09:33:23

Solve the former one first
$- 29 = 5 y - 3 x$ $-29=5y-3x$
Solve for $y$ $y$
Transfer $3 x$ $3x$
$3 x - 29 = 5 y$ $3x-29=5y$
You can also transfer the $5$ $5$ in $5 y$ $5y$ but that would be stupid considering that the next equation wants $5 y$ $5y$
The latter equation
$4 x - 5 y = - 1$ $4x-5y=-1$
Put the value of $5 y$ $5y$
$4 x - (3 x - 29) = - 1$ $4x-(3x-29)=-1$
Which gives us
$4 x - 3 x + 29 = - 1$ $4x-3x+29=-1$
Solve
$x + 29 = - 1$ $x+29=-1$
Transfer the $- 1$ $-1$
$x + 29 + 1 = 0$ $x+29+1=0$
$x + 30 = 0$ $x+30=0$
Which gives
$x = - 30$ $x=-30$
$5 y = 3 x - 29$ $5y=3x-29$
Put value of $x$ $x$
$5 y = 3 \times (- 30) - 29$ $5y=3xx(-30)-29$
Solve
$5 y = - 90 - 29$ $5y=-90-29$
Solve
$5 y = - 119$ $5y=-119$
Transfer $5$ $5$
$y = - \frac{119}{5}$ $y=-119/5$
Or...
$y = - 23.8$ $y=-23.8$

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How do you solve the following system: $- 29 = 5 y - 3 x, 4 x - 5 y = - 1$ $-29=5y-3x, 4x-5y= -1$ ?

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How do you solve the following system: −29=5y−3x,4x−5y=−1-29=5y-3x, 4x-5y= -1 ?

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How do you solve the following system: $- 29 = 5 y - 3 x, 4 x - 5 y = - 1$ $-29=5y-3x, 4x-5y= -1$ ?