How do solve the following linear system?: $- 6 x + 5 y = 1, 5 x - 5 y = 10$ $-6x+5y=1 , 5x-5y=10$ ?

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How do solve the following linear system?: $- 6 x + 5 y = 1, 5 x - 5 y = 10$ $-6x+5y=1 , 5x-5y=10$ ?

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Answer 1 · 2018-05-14T20:09:14

$(- 11, - 13)$ $(-11,-13)$

Explanation:

Since you have $+ 5 y$ $+5y$ in one equation and $- 5 y$ $-5y$ in the other equation, you can add both equations to cancel out the y terms and solve for x.

$- 6 x + 5 x = - x$ $-6x + 5x=-x$
$5 y - 5 y = 0$ $5y-5y=0$
$1 + 10 = 11$ $1+10=11$
therefore
$- x = 11$ $-x=11$
multiplying both sides by -1:
$x = - 11$ $x = -11$

plugging this back into the first equation:

$- 6 (- 11) + 5 y = 1$ $-6(-11)+5y=1$
$66 + 5 y = 1$ $66+5y=1$
subtracting 66 from both sides:
$5 y = - 65$ $5y=-65$
divide both sides by 5:
$y = - 13$ $y=-13$

putting the x-values and y-values into one point gives:
$(- 11, - 13)$ $(-11,-13)$
as the solution

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How do solve the following linear system?: $- 6 x + 5 y = 1, 5 x - 5 y = 10$ $-6x+5y=1 , 5x-5y=10$ ?

1 Answer

Explanation:

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How do solve the following linear system?: -6x+5y=1 , 5x-5y=10 −6x+5y=1,5x−5y=10 -6x+5y=1 , 5x-5y=10 ?

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Explanation:

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How do solve the following linear system?: $- 6 x + 5 y = 1, 5 x - 5 y = 10$ $-6x+5y=1 , 5x-5y=10$ ?