How do you solve #2x-7y=6#, #x+3y=2#?

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How do you solve #2x-7y=6#, #x+3y=2#?

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Answer 1 · 2018-03-28T20:22:27

#(x,y) = (32/13, -2/13)#

Explanation:

#x=2-3y# using the second equation, define x in terms of y
#2(2-3y)-7y=6# plug the above into the first equation
#4-6y-7y=6# distribute
#4-13y=6#
#13y=-2#
#y=-2/13#
Going back to the first equation, we can plug this value in for y to achieve x.
#x=2-3(-2/13)#
#x=26/13+6/13#

#x=32/13#

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How do you solve #2x-7y=6#, #x+3y=2#?

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