How do you solve the system x+6y=-1, 5x+7y=-5 using the substitution method? Algebra Systems of Equations and Inequalities Systems Using Substitution 1 Answer Anjali G Nov 21, 2016 x=-1 y=0 Explanation: x+6y=-1 x=-6y-1 5x+7y=-5 5(-6y-1)+7y=-5 -30y-5+7y=-5 -23y=0 y=0 x=-6y-1 x=-6(0)-1 x=-1 Answer link Related questions How do you solve systems of equations using the substitution method? How do you check your solutions to a systems of equations using the substitution method? When is the substitution method easier to use? How do you know if a solution is "no solution" or "infinite" when using the substitution method? How do you solve y=-6x-3 and y=3 using the substitution method? How do you solve 12y-3x=-1 and x-4y=1 using the substitution method? Which method do you use to solve the system of equations y=1/4x-14 and y=19/8x+7? What are the 2 numbers if the sum is 70 and they differ by 11? How do you solve x+y=5 and 3x+y=15 using the substitution method? What is the point of intersection of the lines x+2y=4 and -x-3y=-7? See all questions in Systems Using Substitution Impact of this question 1326 views around the world You can reuse this answer Creative Commons License