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How do you solve $-2x – 0y = -4$ and $-6x – 2y = -12$ ?

1 Answer

Jun 21, 2016

$(x,y)=(2,0)$

Explanation:

Given
[1] $color(white)("XXX")-2x-0y=-4$
[2] $color(white)("XXX")-6x-2y=-12$

From [1] we have
[3] $color(white)("XXX")-2x=-4$

[4] $color(white)("XXX")x=2$

Substituting $2$ for $x$ (from [4]) into [2]
[5] $color(white)("XXX")-6(2)-2y=-12$

[6] $color(white)("XXX")-12-2y=-12$

[7] $color(white)("XXX")-2y=0$

[8] $color(white)("XXX")x=0$

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