How do you solve the following system?: # 3x-y=4 , 3x - 5y = 2 #

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Answer 1 · 2018-05-18T18:44:57

Lettuce solve #3x#

#1^(st)" equation"#

#3x-y=4#

Transfer #y#

#3x=4+y#
Just remember this value as in the next equation we have #3x# too

#color(blue)(x=(4+y)/3#

#2^(nd)" equation"#

#3x-5y=2#

Put value of #3x#

#4+y-5y=2#

#4-4y=2#

Factorize #4# outta it

#4(1-y)=2#

Transfer #4#

#1-y=2/4#

Transfer 1

#-y=1/2-1#

Common Denominator

#-y=1/2-2/2#

#cancel-y=cancel-1/2#

#color(Red)(y=1/2#

#x=(4+y)/3#

You get

#x=(4+1/2)/3#

Common denominator

#x=(8/2+1/2)/3#

#x=9/2 div 3#

Invert

#x=cancel9^3/2xx1/cancel3#

You end up with

#color(red)(x=3/2#