How do you solve the following system?: $3x-y=4 , 3x - 5y = 2$

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How do you solve the following system?: $3x-y=4 , 3x - 5y = 2$

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Answer 1 · 2018-05-18T18:44:57

Lettuce solve $3x$

$1^(st)" equation"$

$3x-y=4$

Transfer $y$

$3x=4+y$
Just remember this value as in the next equation we have $3x$ too

$color(blue)(x=(4+y)/3$

$2^(nd)" equation"$

$3x-5y=2$

Put value of $3x$

$4+y-5y=2$

$4-4y=2$

Factorize $4$ outta it

$4(1-y)=2$

Transfer $4$

$1-y=2/4$

Transfer 1

$-y=1/2-1$

Common Denominator

$-y=1/2-2/2$

$cancel-y=cancel-1/2$

$color(Red)(y=1/2$

$x=(4+y)/3$

You get

$x=(4+1/2)/3$

Common denominator

$x=(8/2+1/2)/3$

$x=9/2 div 3$

Invert

$x=cancel9^3/2xx1/cancel3$

You end up with

$color(red)(x=3/2$

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How do you solve the following system?: $3x-y=4 , 3x - 5y = 2$

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How do you solve the following system?: 3x-y=4 , 3x - 5y = 2 3x-y=4 , 3x - 5y = 2

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How do you solve the following system?: $3x-y=4 , 3x - 5y = 2$