How do you solve 4y = 28 and 3x – 2y = -14?

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Answer 1 · 2016-01-12T11:47:28

x = 0 , y = 7

When solving a system of equations , it is usual to label them as this makes it 'easier' to follow as operations are performed on them.

4y = 28 ........(1)

3x - 2y = - 14........(2)

From (1): 4y = 28 hence y = 7

substituting y = 7 in (2) gives : 3x - 2(7) = - 14

ie. 3x - 14 = -14 hence 3x = - 14 + 14 = 0 and so x = 0.

The solution to these equations is the point of intersection of the 2 lines and in this case is (0 , 7 )

The following diagram illustrates this solution.

graph{(y-7)(y-3/2 x - 7 )=0 [-40, 40, -20, 20]}