How do you solve $x + y = 5$ $x + y = 5$ and $2 x + y = 7$ $2x + y = 7$ using substitution?

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How do you solve $x + y = 5$ $x + y = 5$ and $2 x + y = 7$ $2x + y = 7$ using substitution?

1 Answer

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Answer 1 · 2018-04-09T11:19:14

$x = 2$ $x=2$
$y = 3$ $y=3$

Explanation:

You can re-arrange equation $x + y = 5$ $x+y=5$ to get $x = 5 - y$ $x=5-y$ and then substitute this into the equation $2 x + y = 7$ $2x+y=7$ to get $2 (5 - y) + y = 7$ $2(5-y)+y=7$ .

This can then be simplified to $10 - y = 7$ $10-y=7$ and so $3 - y = 0$ $3-y=0$ which means $y = 3$ $y=3$ .

Substitute $y = 3$ $y=3$ into $x + y = 5$ $x+y=5$ and you get $x + 3 = 5$ $x+3=5$ , therefore:
$x = 2$ $x=2$
$y = 3$ $y=3$

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How do you solve $x + y = 5$ $x + y = 5$ and $2 x + y = 7$ $2x + y = 7$ using substitution?

1 Answer

Explanation:

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1 Answer

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How do you solve $x + y = 5$ $x + y = 5$ and $2 x + y = 7$ $2x + y = 7$ using substitution?