How do you solve the following system using substitution?: $x = 4 - 4 y, - x + 2 y = 2$ $x=4-4y, -x+2y=2$

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How do you solve the following system using substitution?: $x = 4 - 4 y, - x + 2 y = 2$ $x=4-4y, -x+2y=2$

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Answer 1 · 2015-11-05T13:23:48

y = 1
x=0

Explanation:

First replace all values of x in the second equation with $4 - 4 y$ $4-4y$ (this can be done for y as well but you would need to isolate the variable first)

Which gives you:
$- (4 - 4 y) + 2 y = 2$ $-(4-4y)+2y=2$

Then solve using algebra:
Distribute the $-$ $-$
$- 4 + 4 y + 2 y = 2$ $-4+4y+2y=2$

Combine all all the y values
$- 4 + 6 y = 2$ $-4+6y=2$

Add 4 to both sides
$(- 4 + 6 y) + 4 = (2) + 4 \to 6 y = 6$ $(-4+6y)+4=(2)+4rarr6y=6$

Finally divide both sides by 6
$\frac{6 y}{6} = \frac{6}{6} \to y = 1$ $(6y)/6=6/6rarry=1$

Thus your y value is equal to 1. To find the x value, substitute this 1 into one of the equations for all y's
$x = 4 - 4 (1)$ $x=4-4(1)$

Then simplify
$x = 4 - 4 \to x = 0$ $x=4-4rarrx=0$

thus x is equal to 0

You could also check your answer by substituting both values into the other equation
$- (0) + 2 (1) = 2$ $-(0)+2(1)=2$

$0 + 2 = 2$ $0+2=2$

$2 = 2$ $2=2$

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How do you solve the following system using substitution?: $x = 4 - 4 y, - x + 2 y = 2$ $x=4-4y, -x+2y=2$

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you solve the following system using substitution?: x=4-4y, -x+2y=2x=4−4y,−x+2y=2x=4-4y, -x+2y=2

1 Answer

Explanation:

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Impact of this question

How do you solve the following system using substitution?: $x = 4 - 4 y, - x + 2 y = 2$ $x=4-4y, -x+2y=2$