How do solve the following linear system?: $6 x - 4 y = - 1, 3 y = 15 - x$ $6x-4y=-1 , 3y = 15 -x$ ?

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How do solve the following linear system?: $6 x - 4 y = - 1, 3 y = 15 - x$ $6x-4y=-1 , 3y = 15 -x$ ?

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Answer 1 · 2018-07-10T08:15:57

$x = \frac{57}{22}, y = \frac{91}{22}$ $x=57/22,y=91/22$

Explanation:

Writing the second equation in the form

$x = 15 - 3 y$ $x=15-3y$
plugging this in the first equation

$6 (15 - 3 y) - 4 y = - 1$ $6(15-3y)-4y=-1$
expanding we get

$90 - 18 y - 4 y = - 1$ $90-18y-4y=-1$
substracting $90$ $90$ and combining like Terms

$- 22 y = - 91$ $-22y=-91$
so
$y = \frac{91}{22}$ $y=91/22$

so
$x = 15 - 3 \cdot \frac{91}{22}$ $x=15-3*91/22$

$x = \frac{15 \cdot 22 - 3 \cdot 91}{22} = \frac{57}{22}$ $x=(15*22-3*91)/22=57/22$

Answer 2 · 2018-07-10T08:21:09

$x = \frac{57}{22}$ $x=57/22$ , $y = \frac{91}{22}$ $y=91/22$

Explanation:

The given linear equations

$6x-4y=-1\ ..........(1)$

$3y=15-x$

or

$x+3y=15\ ..........(2)$

Multiplying (2) by $6$ & subtracting from (1) as follows

$6x-4y-6(x+3y)=-1-6\times 15$

$-22y=-91$

$y=91/22$

setting $y=91/22$ in (2), we get

$x=15-3y$

$=15-3(91/22)$

$=57/22$

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How do solve the following linear system?: $6 x - 4 y = - 1, 3 y = 15 - x$ $6x-4y=-1 , 3y = 15 -x$ ?

2 Answers

Explanation:

Explanation:

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How do solve the following linear system?: 6x-4y=-1 , 3y = 15 -x 6x−4y=−1,3y=15−x 6x-4y=-1 , 3y = 15 -x ?

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How do solve the following linear system?: $6 x - 4 y = - 1, 3 y = 15 - x$ $6x-4y=-1 , 3y = 15 -x$ ?