How do you solve the following system: 1/2x - 2y = 4 , 4x + y = 2 ?

1 Answer
May 18, 2018

See a solution process below:

Explanation:

Step 1) Solve the first equation for x:

1/2x - 2y = 4

color(red)(2)(1/2x - 2y) = color(red)(2) * 4

(color(red)(2) * 1/2x) - (color(red)(2) * 2y) = 8

color(red)(2)/2x - 4y = 8

1x - 4y = 8

x - 4y + color(red)(4y) = 8 + color(red)(4y)

x - 0 = 8 + 4y

x = 8 + 4y

Step 2) Substitute (8 + 4y) for x in the second equation and solve for y:

4x + y = 2 becomes:

4(8 + 4y) + y = 2

(4 * 8) + (4 * 4y) + y = 2

32 + 16y + y = 2

32 + 16y + 1y = 2

32 + (16 + 1)y = 2

32 + 17y = 2

32 - color(red)(32) + 17y = 2 - color(red)(32)

0 + 17y = -30

17y = -30

(17y)/color(red)(17) = -30/color(red)(17)

(color(red)(cancel(color(black)(17)))y)/cancel(color(red)(17)) = -30/17

y = -30/17

Step 3) Substitute -30/17 for y in the solution to the first equation at the end of Step 1 and calculate x:

x = 8 + 4y becomes:

x = 8 + (4 * -30/17)

x = 8 + (-120/17)

x = 8 - 120/17

x = (17/17 * 8) - 120/17

x = 136/17 - 120/17

x = 16/17

The Solution Is:

x = 16/17 and y = -30/17

Or

(16/17, -30/17)