How do you solve the following system: $8 x - y = 19, 7 x + 15 y = 32$ $8x-y=19 , 7x+15y=32$ ?

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Answer 1 · 2018-06-20T07:23:36

$x = 2.496, y = 0.9685$ $color(maroon)(x = 2.496, y = 0.9685$

$8 x - y = 19, Eqn (1)$ $8x - y = 19, " Eqn (1)"$

$7 x + 15 y = 32, Eqn (2)$ $7x + 15y = 32, " Eqn (2)"$

$120 x - 15 y = 285, E q n (3)$ $120x - 15y = 285, " Eqn (3)$ , $(15 \cdot Eqn (1))$ $color(crimson)((15 * "Eqn (1)")$

Adding eqns (2) & (3),

$127 x = 317, or x = \frac{317}{127} = 2.496$ $127x = 317, " or " x = 317/127 = 2.496$ #

Substituting the value of x in Eqn (1),

$\frac{8 \cdot 317}{127} - y = 19$ $(8*317) / 127 - y = 19$

$y = \frac{8 \cdot 317}{127} - 19 = 0.9685$ $y = (8*317) / 127 - 19 = 0.9685$

How do you solve the following system: 8x-y=19 , 7x+15y=32 8x−y=19,7x+15y=328x-y=19 , 7x+15y=32 ?