How do you solve the following linear system: $y = 3 x + 8, y = 3 x + 2$ $y= 3x + 8, y= 3x + 2$ ?

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How do you solve the following linear system: $y = 3 x + 8, y = 3 x + 2$ $y= 3x + 8, y= 3x + 2$ ?

1 Answer

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Answer 1 · 2016-03-17T21:40:12

No solution!

Explanation:

The gradient in both cases is 3. Thus they are parallel and do not cross. As such it is not possible for them to share the same coordinates at any one instance.

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How do you solve the following linear system: $y = 3 x + 8, y = 3 x + 2$ $y= 3x + 8, y= 3x + 2$ ?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you solve the following linear system: y= 3x + 8, y= 3x + 2 y=3x+8,y=3x+2y= 3x + 8, y= 3x + 2 ?

1 Answer

Explanation:

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Impact of this question

How do you solve the following linear system: $y = 3 x + 8, y = 3 x + 2$ $y= 3x + 8, y= 3x + 2$ ?