How do you find the solution of the system of equations $x + y = 6$ $x+y=6$ and $x - y = 2$ $x-y=2$ ?

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Answer 1 · 2015-05-19T15:00:53

Let's isolate one variable in one equation and take the value we find and substitute it in the other equation, as follows.

Let's isolate $x$ $x$ in the first, for example:

$x = 6 - y$ $x=6-y$

Nos, substituting it in the second:

$(6 - y) - y = 2$ $(6-y)-y=2$
$6 - 2 y = 2$ $6-2y=2$
$- 2 y = - 4$ $-2y=-4$
$y = \frac{1}{2}$ $y=1/2$

If $y = \frac{1}{2}$ $y=1/2$ and $x = 6 - y$ $x=6-y$ , then

$x = 6 - \frac{1}{2}$ $x=6-1/2$
$x = \frac{11}{2}$ $x=11/2$

How do you find the solution of the system of equations x+y=6x+y=6 and x−y=2x-y=2?