How do you solve the following system?: $-2x+12y=-20 , y=1/3x$

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Answer 1 · 2016-08-23T10:43:13

$x=-10$

$y=-10/3$

$-2x+12y=-20$

or

$2x-12y=20$

or

$x-6y=10$

$y=x/3$

or

$x=3y$

Plugging the value $x=3y$ in the equation $x-6y=10$

We get

$3y-6y=10$

or

$-3y=10$

or

$y=-10/3$ --------------------------Ans $1$

Plugging the value
$y=-10/3$ in the equation $x=3y$ we get

$x=3times(-10/3)$

or

$x=-10$ -----------------------------Ans $2$

How do you solve the following system?: -2x+12y=-20 , y=1/3x -2x+12y=-20 , y=1/3x