How do you solve by substitution #x = y - 1# and #y = 4 - 2x#?

1 Answer

Jun 8, 2015

#{x=y-1#
#{y=4-2x#
Substitute for #x# into the second equation:
#y=4-2(y-1)#
#y=4-2y+2#
#3y=6#
#y=2#
Back into the first equation:
#x=2-1=1#
Solution
#x=1#
#y=2#

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How do you solve by substitution #x = y - 1# and #y = 4 - 2x#?

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